x^2+3x-2650=0

Solution for x^2+3x-2650=0 equation:

x^2+3x-2650=0

a = 1; b = 3; c = -2650;
Δ = b2-4ac
Δ = 32-4·1·(-2650)
Δ = 10609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10609}=103$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-103}{2*1}=\frac{-106}{2}
=-53
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+103}{2*1}=\frac{100}{2}
=50
$